chu văn biên giáo viên chương trình bổ trợ kiến thức 12, kênh vtv2 đài truyền hình việt nam bổ trợ kiến thức luyện thi đại học trên kênh vtv2 vật lí phân loại và phương pháp giải các bài toán cơ bản, điển hình, hay, lạ và khó. phần 2:
T " ^— A^T" CHU VAN BIEN Gi^o vien chuong trinh bo tro Itien thurc V$t li 12, kenh yffZ - Dai Truy^n hinh Viet Nam Bo tra hion IMi « i i LUYEN m DAI HOC IKEN KENHWi PHAN LOAI VA fHUONG PHAP GlAl CAC BAI TOAN CO BAN, DIEN HINH, HAY, LA VA KHO Phan i!: Dltn HOW CHIEU • Danh cho ttn sinh lOp 12 On tap va thi Bai hqc, Cao dang V' Blen scan theo nOl dung va cau tnic 6& tN ciia BO GD E DT, , HA HOI NHA XUAT BAN DAI HOC QUOC GIA HA NQI Cty TNHH mv C h u ae C h u d e B A I T O A N L I E N Q U A N D E N THCJl G I A N 1) Q u a n he gia tri hieu dung 12 B A I T O A N L I E N Q U A N D E N D I E N LLfONG 19 BAI T O A N LIEN Q U A N DEN M A C H RLCNOI TIEP 23 BAI TOAN LIEN QUAN DEN BIEU 37 D I E N PHLfC DIEN VA DIEU KIEN LECH PHA 47 B A I T O A N L I E N Q U A N D E N C O N G S U A T vA H ESO CONG SUAT BAI TOAN LIEN QUAN DEN GIAN D OVECTO DOI CAU TRUC M a c h chi c6 R t h i u va i cung pha va R = ^ = • ••' ''^v^ 'f v 104 132 II; ' • • • ~ " i ' , = (oL = M a c h chi c6 L t h i u som h a n i la M a c h chi c6 C thi u tre h o n i la — va Z^- = Uo lo Uo (oC lo D o i v o i mach chi c6 L , C thi u v i i o n g pha v d i i nen In / u A2 U„ V i du : D a t vao hai dau m o t cuon cam thuan L mot dien ap xoay chieu c6 gia hieu d u n g qua L la 2,4 A De c u o n g d o hieu d u n g qua L bang 3,6 A t h i tan so CLia d o n g dien phai bang A 75 H z U U Chude2 1= MAY DIEN BAI TOAN LIEN QUAN DEN M A Y PHAT DIEN XOAY CHIEU t r i hieu d u n g U k h o n g doi va tan so f thay d o i K h i f = 60 H z t h i c u o n g MACH, B A I T O A N L I E N Q U A N D E N ClJC T R I 1: • 58 71 H O P K I N , G l A T R I TL/C THCfl :: DI^N Phuong phdp giai B A I T O A N L I E N Q U A N D E N M A C H C H I C O R, C H I C O L , C H I C O C BAI TOAN LIEN QUAN DEN THAY Vipt BAI TOAN LIEN QUAN DEN MACH CHI C6 R, CHJ C6 L, CHJ C6 C MACH DIEN B A I T O A N L I E N Q U A N D E N C O N G HUCJNG MACH DWH Khang _ B 40Hz C 25 H z D V H z I , =• I = P H A 200 MI- v ' Ir ^""^'^ ^ f2 = f, 1L = ^ = 40 ( H z ) => C h o n B U I2 3,6 "If'a'l 0'.' IV^ 27:f7L B A I T O A N L I E N Q U A N D E N M A Y PHAT D I E N X O A Y C H I E U PHA 211 BAI TOAN LIEN QUAN DEN DONG C ODIEN 215 hieu d u n g qua mach la 2A Neu mac tu vao nguon u = Ucos(1207tt + 0,5::) BAI TOAN LIEN QUAN DEN M A Y BIEN AP 225 (V) thi c u o n g d o hieu d u n g qua mach la bao nhieu? BAI TOAN LIEN QUAN DEN TUYEN 237 A 1,2N/2A TAI DIEN B A I T A PD I N H T I N H B A I T A PD I N H L U O N G V i du : M o t tu dien k h i mac vao nguon u = uV2 , 286 ' C V2 ""'XHuongdan 253 ^,„rn:.-.:v;.r.r::.::;:::.T;::::.:^^^ , B 1,2A cos(100Kt + 7t) (V) thi cuong A D 3,5 A ••*'-,''-:''>:^'Zr 2) Neu ghep sdt vdo mot bdn tu mot td'm dien moi c6 vd cdc yeu tokhdc 9.10\47r(l-x)d Cwang 1)'-' {A.}S = 'T • ' T khong -X (1-x) 9.10 S tiep: X M a c h c h i c6 L t h i u s o m p h a h o n i la n/2 n e n Z L = coL = —- = — ^ ^ ^ ' i = IQ C O S cot M 47rxd u = U Q C O S cot + — 2, E(1-X) Co- u + Jo; i = I() cos cot V i d u 4: M o t t u d i e n p h a n g k h o n g k h i d u g c n o i v a o n g u o n d i e n x o a y c h i e u t h i c i r o n g d o h i e u d u n g q u a m a c h la 5,4 A N e u n h i i n g h a i p h a n ba d i e n t i c h cac b a n t u n g a p v a o t r o n g d i e n m o i l o n g (c6 h a n g so d i e n m o i e = 2) v a — = 1< = — COC D 9,0 A = U72 u Uo u = — = — ^ — I In 2 + u = 1< Uo = uV2|:;2 cac Do'i vc^i m a c h c h i c6 L , C t h i u v u o n g p h a v o i i n e n y e u t o k h a c k h o n g d o i t h i c u o n g d o h i e u d u n g q u a t u la C 10,8 A = U() s i n cot u = U() cos c o t - 2y ,, In Un : M a c h c h i c6 C t h i u t r e p h a h o n i la n/2 n e n -I X + E(1 - x) B , A = - U Q s i n cot I 2 hieu dung qua mqch luc Id ] ' = u C U = • A 7,2 A = ^ , , = ^ , = ( A ) r:^ C h o n B Q u a n he gia tri tuc thoi E :+ 9.10^.47i.0,3.d 17 C i + C , a M a c h c h i c6 R t h i u v a i c i i n g p h a n e n R = — = ES Cn => c = _ 20C0 ^20^ Q.C2 CintC2 be day bang x phan tram be' dot thi bo tu C gom hai tu Ci, Ci ghep noi C-1^2 ,C, 20 17 '.,1'n B.IOOV 2500 , + —=^ = I„=2(A) — C h e n B y ,, , ,„ tii'VidnmpiS V i d u 3: Dat vao hai dau m o t cuon cam thuan c6 t u cam 0,3/;: (H) m o t dien ap xoay chieu Biet dien ap c6 gia trj tuc thai 60-J6 (V) t h i d o n g dien c6 gia trj tuc t h o i V (A) va k h i dien ap c6 gia t r i tuc t h a i 60>/2 (V) t h i d o n g dien CO gia t r i tuc t h o i %/6 (A) H a y tinh tan so cua d o n g dien A B ( H z ) 120 (Hz) ' ' • 360.6 44=:> Z L = 2nfL = 360.2 ' C 100 (Hz) Huang =1 , — +— ^ =1 dan In I dan 4+4=1 fUo=200 10000 i.4=i = Wf^ """lo =2=>I = V ( A ) = 120V2 Io-2^/2 = 60 ^ f = lOO(Hz) => Chon C t K h i tan so tang gap d o i neu la tu t h i d u n g khang g i a m Ian nen d o n g hieu d u n g tang Ian, tuc la F = = V A N h u n g theo bai F = 0,5 V A = 1/2 nen X = L cho: Z , =2niL 50 =- imi i'" Uo _ 200 ^0 7t L = i(H)=>ChonB V i d u 5: (DH-2010) Dat di§n ap u = Uocoscot vao hai dau cuon cam thuan c6 t u cam L t h i c u a n g d o n g dien qua cuon cam la Uo U U, D 60 ( H z ) (I C rJl_ -^nnan 30000 •2 • on ' '" n A i = HLcos a)t + — coL C i = - ^ cos coL B i = (ot n D i = Huang dan V i mach chi c6 L t h i i tre pha h o n u la n/2 nen (OLN/2 cos 7t a)t + — 7t cos c o t - C LV2 O 2J Bo trfi kien thijrc V,jt li I roil = —^cos cot iren kcnh VTV2 t^p - Chu V^n coL-cos Blen Chu y: Mach ^om L ndi tiep voi C thi dien dp giim hai dau doqn mach u = ui, + uc •Chon C Vi du 6: Dat dien ap u = Uocos(1207Tt - TT/4) (V) vao hai dau mgt tu dien thi von kenhiet (c6 dien tro rat Ion) mac song song voi tu dien chi 120^/2 (V), ampe kenhiet (c6 dien tro bang 0) mac noi tiep voi tu dien chi ( A ) Chon ket luan diing ,i' A Dien dung ciia tu dien la l/{7,2n) (mF), pha ban dau ciia dong dien qua tu dien la n/4 J B Dung khang cua tu dien la 60 Q, pha ban dau ciia dong dien qua tu dien n'; la = 71/2 v h r nM' Wvrl D Dien ap cue dai giira hai dau tu dien la 120 y/l (V), dong dien cue dai qua tu dien la V ( A ) Huong dan Dien dung tu duoc xac dinh tir =— = ^ " ^ coC I A 1207rC I20V2 2V2 =i.C= V i du 8: Mot doan mach mSc noi tiep gom: tu dien eo dung khang Z c va cuon cam thuan c6 cam khang Z i , = 0,5Zc Dien ap giira hai dau tu: uc = 100eos(1007it + 7t/6) V Dien ap giiia hai dau doan mach la: A u = 200eos(1007it - 57t/6) V • •' B u = 200cos(100Txt - 7r/3) V C u = 100eos(1007it-571/6) V D u = 50cos(1007it + 7:/6) V Huong dan , 1+: • |«~.- = thi du'a vao he thi'fc \ V i du 7: Do thj bieu dien cuong tuc thoi cua dong dien xoay chieu chi c6 cuon cam thuan c6 cam khang ZL = 50 Q o hinh ve ben Viet bieu thue dien ap tuc thoi giira hai dau cuon cam ' " hi,;: i ( A ) A u = 60cos(507it/3 + 7t/3) ( A ) B u = 60sin(1007rt/3 + n/3) ( A ) , C u = 60eos(507it/3 + n/6) ( A ) D u = 30cos(507rt/3 + Tt/3) ( A ) hoac Uo=IoZc Mach chi c6 C thi i sdm pha hcfn u Id K/2 Mach chi c6 L thi i tre pha hcfn u Id n/2 •1 • 2) Neil cho ii;i2 ui;u2 thi dim vao he thuc /.I 44Uo=? T2 TT2 (I J Uo Mack chi c6 C thi i sdm pha hcfn u la TZ 12 vd ZQ = coC Mach chi coLthii tri pha hem uldn/2vdZi=(dL Huong dan 5071 • \% -n,.:,, T • \ Vi mach chi eo L thi u som pha han i la 7t/2 nen 507rt 71 71 • C = ? O In 150 V thi cuong dong dien mach la A Bieu thuc ciia cuong 27t i = — den i = Old — = = 0,01 12 12co , co = ? dien CO dien dung 0,2/7t (mF) thoi diem dien ap giua hai dau tu dien la = — ycidang.dive i = 0nernp = — Thdi gian ngdn nhdt ditii = IQ V i du 9: (DH-2009) Dat dien ap u = Uocos(1007rt - 7t/3) (V) vao hai dau mot tu i = IQ cos (cot + cp) = 1,2 cos (cot + cp)(A) Liicdau,i • Z L + u^ Thay U Q ^ I Q Z L = 1- (F) Vi mach chi c6 C thi i som pha hon u la n/2 nen 1207rt-^ + ^ 120Trt + • Chon A i = I>/2cos 1207tt + - =4cos :fUSU.:dt' Up u = -0,5uc + U c = 0,5uc = 50 cos 1007Ct + - (V)=>ChonD j j i ,:v 6, Chu y: (dm) in:t)\i ^n;.iC) !'-/2 cos(1007rt + 7r/6) ( A ) B i = 5cos(1007rt + 7t/6) ( A ) C i = 5cos(1007tt - 7r/6) ( A ) D i = V2 cos(1007rt - 7t/6) ( A ) h/.'AM.ii'^y'AH Cdch 1: Gidi tuan tu: 1 Huongdan );|^:Kr;i;flj!p*iJ,r.):^i;^»;.fi!a iriJ'rrs! hamh it'jil: ••.!,!'• : :: , Bo trfl kicn Ihitc V^t li LTDH tren hcnii VTV2, \ / => C O S l O O T l t - u = I Q Z C COS l O O T l t - - 3/ \ = u + sin l O O T T t V 2J -1 [1,50 Cdch 2: Gidi nhanh (van J Cty Bicn IQZC u = I Q Z , ^ cos -i 3y u, ^5.10 + ^2 150 Thny U() = l o Z c -4 _3^ = 0 V c o s f l 0 t ' ' " ^ - - l = 0 V ( V ) •I 6y lOOKt In 50 chieu Biet dien ap c6 gia t r i tiic t h o i 60^6 = t h o i yfl (A) va k h i dien ap c6 gia t r i tuc t h a i SOs/l (V) t h i d o n g dien c6 gia t r i tuc t h o i -^6 ( A ) Ban dau d o n g dien tuc thoi bang gia t r i cue dai, bieu thii'c C L i a d o n g dien la + A ( s ) ( k = 0/1,2 ) 240 50 t = 1200 3) Ta thay: 2014 + — ( s ) ( l = 1,2,3 ) 50 = 1006 d u => t = 1006T + , De t i n h t2 ta c6 the d u n g v o n g tron l u g n g giac: A i = 2^y3cos(^007tt + 7t/2) ( A ) B i = V2 coslOOTtt ( A ) C i = V c o s i t ( A ) D i = ^/3 cos(507it + 7r/2)(A) Huong 360.6 360.2 10071 CO Up coC I„ rad • CO = 50TC 200 (s) t = 1006.0,02 + — = 20,135 (s) 200 ' ^> , , 2K + - (t>, - On , dan Uo=120V2 + 1.271 6, (V) t h i d o n g dien c6 gia t r i tuc ^/2 = -+k.27T lOOTit I„=5(A) i = 5cos 100Ttt + - ( A ) : ^ C h o n B V i d u 10: Dat vao hai dau tu dien c6 dien d u n g 1/{3n) (mF) m o t dien ap xoay Vift = 600V2cos[ l O O T i t - - | ( V ) V j 2) Giai p h u o n g t r i n h : u = 600 (V) => cos l O O T t t - - = 1- Kliang MTV DVVH => In = A => i = 5cos 1007:t + - V i mcich chi c6 C thi i som pha hem u la TI/2 nen 2 tat): D u a vao he thuc: -4r + Tnnn V i mach chi c6 tu dien nen dien ap tre pha hon d o n g dien la n/l: u ( \ i = IQ cos t^p - Chu Vdn 4) Ta thay: 2014 = 503 du: => t = 503T + t j De t i n h t2 ta c6 the d u n g v o n g t r o n l u o n g giac: V i ban dau d o n g dien tiic t h o i bang gia trj eye dai, bieu thiic ciia d o n g d i e n CO dang i = I,, cos cot thay so vao ta d u g c i = 2V2 COSSOTTI ( A ) => Clion C V i d u 11: Dat vao hai ban tu dien c6 dien d u n g 100/(37r) (|aF) m o t dien ap xoay 27t O , - On t , _ ^2 = CO lOOTt (s) = > t = 503.0,02 + 120' ' • 120 chieu u = Uiicos(1007it + (pu) (V) t h i d o n g dien qua t u c6 bieu thuc CM i = V cos{1007tt + 7x/3) ( A ) loan cho dien ap (dong dien) a thai diem tim dong dim 1) T i n h d i e n ap g i i i a hai ban t u tai t h o i d i e m t = (ms) 2) Xac d i n h cac t h a i d i e m de dien ap u = 600 (V) » 3) Xac d j n h t h o i d i e m Ian t h u 2014 de u = -300 V2 (V) 4) Xac d j n h t h o i d i e m ian t h u 2014 de |u| = 300 V2 Huang 1) T i n h d u n g Ichang: Z c = — = 0 ( Q ) coC dan (V) t• 6041 600 y: Vi v6i mach chi chiia L hoqc C thi u va i vuong pha nen thuang c6 bai (dien dp) a thai diem triivc hoqc sail mot khoang thai gian (vuong pha) A t = (2n + l)T/4: U2 I ',/ V i d\ 12: D a t vao hai dau doan mach chi c6 cuon cam t h u a n c6 d o t u cam 0,4/7t (H) m o t dien ap xoay chieu u = UocoslOOTct (V) N e u tai t h a i d i e m ti dien ap la 60 (V) t h i c u o n g dong dien tai t h o i d i e m ti + 0,035 (s) c6 Ion la A 1,5 A B 1,25 A C 1,5 V3 A D V2 A Cty B S tr^ kieti thUc V^t II LTDlt tteti k&nh VTV2 t$p - Chu VSn Bi&n Huong 71 =0,035 = — Cam khang Z, = w L = ( Q ) V i t2 60 pha nen: 40 dan = l , ( A ) = > C h o n A V i du 1: Dat dien ap xoay chieu c6 trj hieu d u n g 120 la hai thoi d i e m v u o n g m o t dien ap xoay chieu u = UocoslOOnt (V) N e u tai t h a i d i e m ti dien ap la 50 (V) t h i c u o n g d o n g dien tai thai d i e m ti + 0,005 (s) la: B , A C 1,5 A Huong z, =• (oC = i '(t]+0,005) 1007rt + - COS •(ti+0,005) - D 0,8 (s) T h o i gian hoat d o n g s: b arccos 12071 U,) 2/;^"^t!::'''';:''^^'^'''^^ 60V2 = 60.4 Bie't den sang k h i dien ap =50 A 0,5 Ian 1007i(ti+0,005)- ° 7= = —(s) => Lnon 120V2 L '' dat vao den khong nho h o n 155 V Ty so giCra 100 filsJ , (|„., ,>|' ,| ^0 ' T h a i gian hoat d o n g t r o n g m o t chu k i : t^ = 41, = 4.—arccos— thai CO gia tri bang 0,5Io vao n h u n g thai diem j B 1/400 s v a 2/400 s dan K h i bai toan chi yeu cau t i m hai thai diem dau c6 the giai p h u a n g trinh sin (cot + cp) = s i n a = Un l u o n g giac: arccosi • D 1/600 va 5/600 s I Huang b T h a i gian hoat dong t s: thj = t.f.4.—arccos— (s) ;' losinlOOTit T r o n g khoang thai gian tCf den 0,01 ? c u o n g d o n g dien tiic t ' d i j n g v o n g t r o n l u o n g giac A 1/300 s v a 2/300 s -? C 1/500 s va 3/500 s ''''"^ U(, ~ • ,:, De xac d i n h cac thoi diem c6 the d u n g giai p h u o n g t r i n h l u o n g giac hoac Thoi gian hoat dong s: ft^ = f.4.—arccos — v V i du 1: (DH-2007) D o n g dien chay qua m o t doan mach c6 bieu thuc i = b T h a i gian hoat d o n g t r o n g m o t nua chu k i : 2t, = —arccos-—- —T 2T 2) T h a i diem de dong dien hoac dien ap nhan mot gia tri nhat dinh chi hoat d o n g k h i u nam ngoai khoang (-b, b) (xem h i n h ve) CO D Ian tt chi hoat d o n g k h i dien ap tuc thai c6 gia t r i k h o n g nho h o n b Vay thiet bj CO Ian dan T tT h o i gian den tat m o t chu k i : t, = T - tj^ = — => — = => Chgn B rfniiiaO, M o t thiet bj d i e n duoc dat d u a i dien ap xoay chieu u = Uocoscot (V) Thiet b i " C ^ T h o i gian den sang m o t chu k i : ^ b T 155 t, = 4.—arccos = 4.—arccosCO 2n 220V2 r' i;*, ' ' * • p , B Ian Huang lift: ^- = - , ( A ) =>Chon A 1) T h a i gian thiet b i hoat dong , • dan khoang thai gian den sang va khoang thoi gian den tat t r o n g m o t chu ky la Phuangphdpgidi HtU „ V tan so'60 H z vao hai V i du 2: Mc)t den o n g su d u n g dien ap xoay chieu c6 gia trj hieu d u n g 220V BAITOAN LIEN QUAN DEN THOfI GIAN ;0 r C.2/3(s) Huong CO dan ;„••• , B l/3(s) t = f.4 —arccos D.-1,5A = 0 Q ; u = Uo cosl00Tit=i> U(f^j = U , , coslOOTtti cos Vlft dau m o t bong den h u y n h quang Bie't den chi sang len k h i dien ap dat vao A l/2(s) V i du 13: Dat vao hai dau doan mach chi c6 tu dien c6 dien d u n g 0,l/7i (mF) A.-0,5 A M I V U VVH Khang den k h o n g nho h o n 60 N/2 V T h o i gian den sang m o i giay la: -./c',,; r-iT- Train T arcsin^ ' arcsin^ ! '—* arccosS- cos(o)t + cp) = c c « a : j cot + cp = a + (271) o,t + (p = r - a + (27i) ^P^^fk^''^ cot + (p = a + (2?:) „: , ojt+ = - a + (27t) (Neu t i m t < m o i cong ? : ) O b — arccos — b —arccos — i = Iosinl007it = ^ (s) 600 => Chon D -(s) ^J^'' 1007tt = — = > t = 600 1007rt = - : t = 13 B6 trff kiSn thCrc V^t l i L T B t l trSn kSnh VTV2 t^p - Chu VSn Cty Bien Timti nrv DVVH Khang Vipt V i du 2: D i e n ap hai dau doan mach c6 bieu thiVc u = 200cos(1 OOTit + 57r/6) V i du 4: D i e n ap giua hai dau m o t doan mach ccS bieu thuc u = U()COS(2TTt/T) (u bang v o n , t d o bang giay) T r o n g ii - O =• ^ t= -—(s) Chon A (Neu k h o n g cong them 2n V r Cac t h a i d i e m ma u = 0,5Uo va dang tang t h i chuyen d o n g t r o n deu nam o 1007rt + — = - - + 27i=>t = — ( s ) 600^ ^ 100 ] B 12055.T/6 Huotig dan Cdch 1: Gidi phumig trinh luong gidc Lan ,-\y-'''' D 1/200 va 7/600 s Huong dan u = 100=^ cos lOOTTt '• A 12089.T/6 B 1/400 s va 2/400 s \f|s^,,i;,:, C 1/500 s v a 3/500 s , i 12083T + 20131 = • ChonU V i du 5: D i e n ap giua hai dau m o t doan mach c6 bieu thuc u = Uocos(2Tit/T) dong: Ti'nh t u t h o i d i e m t = s, t h i thoi d i e m lan t h u 2010 ma u = 0,5U() va dang + 2Tt nen thoi gian: giam la 71 „ 5T: - - + 271 - - - 0) Lan 10071 A.6031.T/6 V i t r i xuat phat: „ dien ap tuc thoi c6 gia t r i bang 100 V u n g v o l pha dao d o n g : 71 57r Lan 3^^^"T 2 = — + 27T nen thoi gian: t = ^ - O o w 10071 200 V i du 3: D i e n ap giCra hai dau m o t doan mach c6 bieu thuc: u = 120sin]007rt TT Lan 2010 (u bang v o n , t bang giay) H a y xnc d j n h cac thai d i e m ma dien ap A t = J/3 + k ( m s ) B t = l/6 + k ( m s ) C t = l/3 + 20k (ms) = ( IOOTT.O) = '" " ' T/6 ^'tW)-' • , , , ,^ V i du 6: Dat vao hai dau doan mach m o t dien ap u = UocoslOOrct (V) T r o n g D t = 5/3 + 20k (ms) '* Hicangdan , u = 120sinl007tt = 60 71 ' ' hihm^:r>: , i n n „ => OOTlt = — + k27t u = 1007i.l20cosl007rt>0 , ^ -+k 10' (ms) = - + k ( m s ) => C h o n D =>t = +k (s) = 1600 100 J 600 100 dan Huang D 6025.T/6 T ma u = 0,5Uo theo chieu am: t, = — 2010 ma u = 0,5Uu theo chieu am: =>ChonB u = 60 V va d a n g tang ( v o i k = 0,1, 2, ) C 12059.T/6 '< 600 B.12055.T/6 chu k i t h u cua d o n g dien, cac thoi d i e m dien ap tuc t h o i u c6 gia t r i bang dien ap hieu d u n g la A 0,0625 s va 0,0675 s V C.0,0025 s va 0,0075 s % •I ' ••/ j ' •"' B 0,0225 s va a0275 s D 0,0425 s va 0,0575 s Huang dan Cdch 1: Gidi phuang trinh luong gidc ' ; Bidttff USn thiic V^t It LTDH trSn kenh VTV2 t4p - Chu Van Cty Timii Blgn Chu y: Trong mot chu ki c6 tliai diem de /u / =b< = j = i > t i =0,0025(s) C h u k i t h u 1: u = n md lul •COSl007tt = - = - j + 27r=>t2 = a ] ( s ) It^ = t + T = 0,0375(s) ti = ^ Id : => to = _^ = 0,0225(s) '?r.' :.}:£rifiJ i '' ^^"'^ Lan vd 4n + den la 4n + den la + tj W j la : i^^x+Z = nT + t : t , - , + = nT +13 t4 Solan : t n + = nT = n t t4 = nT + tj neu dif = > t = nT + t2 neu d u = > t = nT + t3 => t :2 A, = n T +14 t i u ^ i = t i + nT Ta co the ,., [ n e u d U = > t = nT + t2 rut 'meo' -'iiu/ ••) f:V dan •' 2013 = 503 d u ^ t2oi3 = 503T + tj Ta d i i n g v o n g t r o n l u g n g giac de t i n h t i : \' T Idm 24 , „ , ' ^hmr (A) £ , v D t = 12073/1200 (s) Huong Ta nhan tha'y: - gt) B t = 9649/1200 (s) K:V-M C t = 2411/240 (s) Do do, chu ki dau tien c6 hai thai diem ti ti; chu ki thu c6 hai tlwi diem = t i + nT + den • diem tren true ung vai hai diem tren vdng trdn lugng gidc (trit hai vi tri Men) t2i,vi 4n = nT t4„+] A t = 12043/12000 (s) (A) Chii y: Ncu khong han chcboi dieu kien dang tang hoac dang gidm thi ung v&i mot t4 = t i + T; Id: dp d o n g d i e n tuc t h a i bang c u a n g d o n g d i e n hi^u d u n g la t5 = t i + T = 0,0425(s) Chu k i thiV 3: ^ ^ => Chon D tg = t + T = 0,0575 (s) • , , So l a n f neu dU => t = nT + t, nhanh: • = n(cot + cp2) = - 92) = - ' D u a vao v o n g l u g n g giac, hai d o n g dien xoay chieu c6 cung t r i tuc thai 0,5 ^/3 lo, d o n g d i e n dang g i a m iVng v o l niia tren d o n g dien dang tang l i n g v o i nua d u o i H a i d o n g dien lech pha la Acp = — • ' , d a n g g i a m t h i sau it nhat la bao lau t h i i = + V6 A? A 3/200 (s) LA1 i ' l = - W I Q sin(cot + (pi) > Cdchl: V i d\ 3: D o n g dien xoay chieu chay qua m g t doan m a c h c6 bieu thiic 1= sfl Ava i,=IoCos(cot.cpO = - ^ ^ ^ ^ ^ ^ ^ ^ ^ _ ^ Acp = - => Chon A COS 1207rti + - = COS V,;, i '2 = -COIQ sin (cot + (p2 ) < C u a n g d o n g d i e n a t h o i d i e m t = ti + 1/240 (s): dan :"'=,'"v;:r Cdchl: Z D.7C/2 C 7t Huong Tai t h o i d i e m ti nao do, d o n g dien c6 c u a n g = 4cosl207tti = 2V3 • =— ^ = (s) => Chon A ' ' 0) lOOTt 200^ V i du 4: Vao cung mot thoi diem nao hai dong dien xoay chieu h = Iocos(cot + cpi A 7t/3 bieu thiic i = 4cos(1207it) (A), t bang giay Huong - ^ + 2TC-~ A q tang m o t d o n g dien dang giam H a i d o n g dien lech pha n h a u V i du 2: D o n g d i e n chay qua m o t doan mach c6 c u a n g d o n g dien bang J- - va i2= Incos(cot + 92) CO ciing trj tuc thai 0,5^/3 lo, n h u n g m o t d o n g dien dang ,,, 2V3 A D e h t h a i d i e m t = ti + 1/240 (s), Vl^, B A I T O A N L I E N QUAN DEN D l | N D 1/100 (s) Chon A LlT^NG Phuong phdp giai 1) Dien lugng chuyen qua tiet dien thang day dan Theo d i n h nghia: i = ^ dt dq = i d t D i e n l u g n g chuyen qua tiet dien thang ciia day dan t i n h t u t h a i d i e m ti den Cty TISHH nrv Bo trp kien thiic V^t liLTDIl VTV2 t^p - Chu tren henh VSn u = I()Zcos(cot + V i dy 19: D a t di§n ap 200V - 50Hz vao hai dau doan mach A B g o m dien t r o t h u a n 25^2 mSc n o i tie'p v o i doan mach X C u o n g d o d o n g d i e n hieu d u n g ^ t=to ; b) N e u cho u = U,)Cos(cot + (p^,) t h i i = -^cos(a)t + ip^ - (p) ', Huang dan u = 200 Lid u tang ; " M N =IoZMNCos(cot + ( P i + M N ) ap giua hai dau doan mach A B so v o i d o n g d i e n qua mach va cong sua't tieu u = 200^/2coslOOTtt- xiU • U c =IoZ(;COs(cOt + (Pi - l / ) tuc t h o i qua doan mach bang A va dang g i a m T i n h lech pha ciia dien .ft;., + cp) a) Ne'u cho i = Iocos(cj)t + cp;) t h i U L =IoZLCos(cot + j + i / ) CO gia t r j 200V va d a n g tang; thoi d i e m to + 1/600 (s), c u o n g d o d o n g dien „•-,,,,,.• Vi^t U ] ^ =I()Rcos(cot + ( p = — > : u sdm hon i Id — , .4, 7C Chon A (V): g i i i a hai dau doan mach chiVa cuon day va t u d i f n A ULrC = 60cos(1007it - 71/3) (V) B ULrC = 60cos(1007it + 7l/4) (V) C U L r c = V c o s ( 0 : t - t / ) ( V ) D U L ^ C = 60 V2 cos(1007it + 57r/12) (V) Huang ZtrC = U OMN Zc + ( Z L - Zc f tan(pLrC = ?^ ZMN - Z tancpMN = - Z bieu thuc i = 2cos(1007:t + 7t/6) (A) (t d o bang giay) Viet bieu thuc dien ap Viet bieu thirc theo phimng phdp truyen thong: U OR Z, = 1572 • u = IijZcos 'l007rt + ^ + ^ l = 2V2.I5V2COS 1007rt + 4J 2) B i e u thiic dong di^n va di^n ap Un dan 30Q va CO cam k h a n g 40Q, t u dien c6 d u n g k h a n g lOQ D o n g m g c h chinh c6 7t n = -=>(p = — 4-,.i V'V:'' Io = r V i du 2: M a c h dien xoay chieu g o m dien t r o 30 Q, cuon day c6 d i e n t r o thuan >u = 400 ( V ) t=o+ ' B u = 30 V2 cos(1007it + 7r/4) (V) mach X C u o n g d o n g dien hieu d u n g qua doan mach la A Biet t h a i d i e m t, dien ap tuc t h o i giua hai dau A B c6 gia t r i 400 V ; t h a i d i e m , , A u = 60cos(1007tt + 71/2) (V) MN R MN -z / r =1 r dan = 30V2Q => cpLfP = — > HI lu : ULrC h^'^ ^ , ~ 57t (V) " L r C =IoZLrCCOS 1007rt + ^ + ^ = 60^y2(cos 1007tt + 12 4, • C h o n D 31 Cty Bo trp klSn thiic V^t li LTDH trcn henh VTV2, t4p - Chu V0n Vi du 3: Mot cuon day thuan cam c6 tu cam 1/n (H) va tu dien c6 dien d u n g 2.10-'/TI (F) ghep noi tie'p, roi no! hai dau doan mach vao nguon c6 dien ap u = 100 V2cos(1007it + Tt/6) (V) Dong dien qua mach la A i = 2cos(1007it + 71/2) (A) C i =2 ^/2 cos(100Ttt - 71/3) (A) D i = V2 cos(1007Tt + 7t/2) (A) Huong dan w o r b w^l/i (cf "ri'T,''!' *• ^••••I'rrin'J wC Z= +(ZL tan (|) = Z, - Z r —^ U, = 50Q -Zc)^ = - 7t irii (o + }fc)r!',o,.^f,,,,0 ,„>^fU or!'; ir^VI (./ , TT •jV'ub ,h>*v sC/n p/ia /iCw ila— , , , +cx)=>(p = — > : i i U68 H'-iii (A)=>Chon C.iBfil-'i^r,:* canJ 2, Vi du 4: Mot doan mach gom cuon day c6 tu cam 0,6/7i (H) mac no'i tiep vai mot tu dien c6 dien dung 1/(14?:) (mF) Dat vao hai dau doan mach mot dien ap xoay chieu c6 bieu thuc: u = 160cos(1007it - 71/12) (V) thi cong suat tieu thu mach la 80 W Bieu thuc cuong dong dien mach la A i = 2cos(1007it - 7i/6) (A) B i = 72 cos(1007tt + n/6) (A) C i = V2 cos(1007:t + 7i/4) (A) D i = V2 cos(1007it - 7c/4) (A) , , Huong d^n ^ ^ 7t -COS 1007rt + ZL =(OL = 60(Q);Z(- = A auii U^R 7t lOOTTt = 140(Q) coC • A i l ,•1" \y.o • => 80 = • P = I^R = R^+(ZL-Zcf •"it tanq) = — Z= R 80-.2.R • ' ) ) R = 80(Q) pha han i let —(i sdm pha hcfh u) + ( Z L - Z ( ; ) ^ = 80>/2 ( Q ) i i = — c o s lOOTTt- — + - =V2i cos 1007tt + 12 (A)=>Chon B 6J Vi du 5: Dat dien ap xoay chieu u = 10cos(1007it + 7t/4) (V) vao hai dau doan mach noi tie'p gom mot tu di^n c6 dung khang 30Q, dien trd thuan R = lOQ, va cuon day c6 di^n tra thuan lOQ c6 cam khang lOQ Viet bieu thiic di^n ap giiia hai dau cuon day A ucd = 5cos(1007it + 37C/4) (V) B ucd = 200 ^/2 cos(1007tt + n/6) (V) C Ucd = 200cos(1007tt + Tc/6) (V) D Ucd = 5cos(1007it + 7t/4) (V) f9 32 ZL-ZC Vift = V ( Q ) z,d =Vr^Tzf = ioV2(n) , n tanked = — = l=>(Pcd = r Bieu thuc u^d som hon u la cp^j -(p = ^ vaUocd = ^ ' ^ c d " ^^^ ^^"^ = ^(^) 371 Dodo: u,a =U(,cdCos = 5cos 1007lt + (V)=^Chon A Vi du 6: (DH-2009) Dat dien ap xoay chieu vao hai dau doan mach c6 R, L, C mSc noi tie'p Bic't R = 10 Q, cuon cam thuan c6 L = 0,1/71 (H), tu dien c6 C = 0,5/7t (mF) va dien ap giita hai dau cuon cam thuan la ^^ ui = 20 V2 cos(l 007it + 71/2) (V) Bieu thuc dien ap giira hai dau doan mach la A u = 40cos(l OOTtt + 7t/4) (V) B u = 40cos(1007ct - 7t/4) (V) C u = 40 N/2 cos(l 007it + 71/4) (V) D u = 40-Jl cos(1007it - 7:/4) (V) Huong dan ^ Z, =coL = 10(Q);Z(;- = ^ = 20(0) [Z = R ' + ( Z L - Z C ) ' = 1072fi 71 z,-z - ^ = -l=>(n = 7: ^^'.^fa'^" tan (p = R Dien ap u tre hon i la 7r/4 ma i tre pha han UL la 7r/2 nen u tre pha hon U L la -Z = 40(V) 371/4 va U(, = z, r i +(60-140r ^ = -1 =>q) = — V VII Khang Huang dan Z = ^{R + rf+{Z^_-Zcf B i = 2cos(100Tit - 7t/2) (A) Z, =wL = 0 Q ; Z c = — = 50Q Timn Blen Do do: u = UnCos ( 1007Ct+ n 3n^ f A (V)^ChonB = 40cos l O O T t t - - y l ; Vi du 7: Doan mach Ixoay chieu khong phan nhanh 4gom cac phan tu theo dung thu tu: dien trd thuan 30 (Q), cuon day thuan cam c6 tu cam 0,6/7c (H) va tu dien CO dien dung IOO/TI ().iF) Dien ap giiia tren doan mach chi gom cuon cam va tu dien c6 bieu thuc ULC = 160cos(1007rt - 7t/3) (V) (t bang giay) Bieu thuc dong dien qua mach la A i = 4V2 cos(1007tt + 7t/6) (A) B i = 4cos(1007tt + 7t/3) (A) C i = 4cos(1007tt - Ti/6) (A) D i = 4cos(1007tt + n/6) (A) : ih : ' Hudtigdan '-.} / ZL = w L = 60Q;Zc = tancpL^; = hon) Z, - Z = 100Q; ZLC = ^ - ^ C ) = 40 = Cty TlSHtlnrvDVVHKhang VTV2 t$p - Chu VHn Bien = 4cos lOOrtt- (A)=>Chon D V i du 8: (DH-2010) Dat dien ap u = Uocoscot vao hai dau doan mach gom dien tro thuan R, cuon cam thuan c6 tu cam L va tu dien c6 dien dung C mac noi tiep Goi i la cuong dong dien tuc thoi doan mach; u , , U va V i du 11: Dat dien ap u = U(icos(cot + 7i/4) (V) vao hai dau doan mach gom dien tra thuan R va cuon cam thuan c6 tu cam L mac no'i tiep thi cuong dong dien qua doan mach la i = Ii)sin(ci)t + 57r/12) (A) Ti so dien tro thuan R va cam khang cua cuon cam la A 1/V3 B C.0,5V3 D V Huong dan U Ian lugt la dien ap tuc thoi giira hai dau dien tro, giua hai dau cuon cam va giCra hai dau tu dien He thuc dung la A i = - \ • ^ ^ R2 + coL - • (oC D i= — ^ Chon C V i du 9: Mot doan mach gom cuon day c6 dien tro thuan 100 Vs Q, c6 tu ' „ cam L noi tiep voi tu dien c6 dien dung 0,00005/7t (F) Dat vao hai dau doan mach mot dien ap xoay chieu u = Uocos(1007rt - Tt/4) (V) thi bieu thuc cuong dong dien tuc thoi qua mach i = V2 cos(1007tt - 7c/12) (A) Xac djnh L , A L = 0,4/71 ( H ) B L = 0,6/TI ( H ) cot + 12 on n C L = 1/n ( H ) D L = 0,5/:: ( H ) Z L = lOO(Q) =0 L = - ( H ) ZL-200 _ IOOV3 L V3 Chon C noi tiep gom dien tro R = 50 Q, cuon cam thuan L va tu dien C thi dong dien •'V; i ' qua mach c6 bieu thuc i = V2 cos(1007rt + 7t/4) (A) Goi U L va = 50V2 V Ian luot A.I2V5V D.UC-UL = 100V2 V C.30V2 V D 60 V Cdch 1: ; I2 ^ = , ; i j som pha hon u; -2C U2LC = U L - U C = U l R z O Z L - ZC = R UILC = U I C - U H = U2K r : i > Z c - Z l , = R R = t a n — = > U C - U L = 100(V) IR 12 tre pha hon u; I , 112 (1) (2) Tu (1) va (2) => Z L = 2R; Zc = R Ban dau tan ( - c p i ) = ZL-ZC u OKL Z = Z RL VR" - X J R ^ + ( R - R ) ^ =60(V) =>ChonD +4R ^ ^ Cdch 2: Huong dan (p = - R B.6V5V Uo = I„Z = B Uc - U L = 100 V ^ , r- V i du 12: Mot cuon day khong thuan cam noi tiep voi tu dien C mach xoay chieu c6 dien ap u = Uocoscut (V) thi dong dien mach s6m pha hon dien ap u la c|)i va dien ap hieu dung giira hai dau cuon day.la 30 V Neu thay C i = 3C thi dong dien cham pha hon u goc c|)2 = 90" - c|)i va dien ap hieu dung giua hai dau cuon day la 90 V Tim Uo , la dien ap hieu dung tren L va tren C He thuc diing la C.UL-UC n Z, 12 y V chieu cua tren I la 0,^ V i du 10: Dat dien ap xoay chieu u = U V2 coslOOnt (V) vao hai dau doan mach A U L - Uc = 100 V = I„cos M t - Huang dan r.r.r.,^^ ^ Zr-Zc - (oC = 0 ( f i ) ; = 9^,-cpi = — =>tan(p = - ^ R c _ ^ / 2, (Ot + Huang dan " n 12 = locos 75 (oL •;'ir-: Chu y: Neu eho biet bieu thuc u, i thi ta se tinh duge trakhdng • , 03t + — ftifi '.pil ^opt "^hn Huang dan Chi Ui Cling pha vdiineni- U = UyCOS i = I n sin I ' i (>,f'i/ ;.j';Hn Vl^t Zi - Z r < => -~ t a n (Pi = ZC-ZL Chon B R / J Chu ij: Neu c6 dang sin thi doi sang dang cos: sin (cot + a) = cos cot + a — = IZ„, = u R^+Z 'R-+(Z,-Zcf = 30 W4 A) Hinh tUi trp kiSn thiic V$t IILTBH Cty TISHll nrv DVVH Khang trSn henJt VTV2 t4tp - Chu VSn Blen Vlft = 90 K K ^-MN ZMN Z M N T h e o b a i r a : + = " n e n tan(pitan(p2 = h a y B i e u t h i i c d o n g d i e n : i = =• = — ^ ' ^ ^ ^ ^ = => R = J ( Z c - Z L ) ( Z , - Z c / ) Cai dat tinh toan vai sophitc Zc^ U' cd U cd z, - " ^ R2+(ZL-Zcr ; Z, R2 + (ZC-ZL) - (ZC-ZL) + (ZL-ZC)' z, - (ZC-ZL) + = =^ Z c = , Z L ^ R = , Z L , Zc^ j.^; + 90 + ^.^^^^ gj.^ j Zr ZMN may tinh casino fx-570es !_ ( D e cai dat t t i n h toan v d i s o p h u c ) t i B A M M O D E B A M 30 ••MN Z, V SHTFT M O D E B A M SHTFT ( D e cai dat h i e n t h i so p h t i c d a n g A Z ) ( D e cai dat d o n v i goc l a r a d ) M O D E 1) l ^ n g d u n g v i e t b i e u t h u c V i d u 1: D a t m o t d i e n a p x o a y c h i e u u = 200cos(]007it + 7i/3) ( V ) v a o h a i d a u m o t d o a n m a c h m a c n o i tiep g o m t u d i e n co d u n g k h a n g 50Q, d i e n t r o T h a y g i a t r j n a y v a o b i e u t h u c UCJ: , ,fl t h u a n Q v a c u o n c a m t h u a n c o c a m k h a n g lOOQ T i n h t o n g t r o c i i a m a c h D i e n a p giCra h a i d a u d o a n m a c h s o m h a y t r e p h a h o n d o n g d i e n t r o n g (0,5Z,,)^+Zf^ = 30=>Uo = ( V ) mach bao nhieu? Viet bieu thuc d o n g dien mach V2^(0,5ZL)'+(ZL-2,5Z,J Huang dan BAI TOAN LIEN QUAN DEN BIEU DIEN PHl7C Ccich 1: Cdch truyen Dang phuc may Bi'eH thuc FX-570 Tong tro tancp = f f n ' n j i :J5 = A/I^MN + ( Z L M N " Z C M N ) Z M N = I^MN + ' ( Z L M N Zl - Z p R - 50V2 ( Q ) ^ 7t „ , , v 'V 4 200 = c o s 1007rt + ^ - ^ = 2^/2 cos 4, ~ ^ C M N ) t = lr=>(p = — > : u sdm h d n la — ( v o l i la s o a o ) Z M N Z = ^R^ + ( Z L - Z C f Z = R + i(Z, - Z ^ ) Z =7R^+(Z,,-Z,)^ thong 1007tt + n 12 i t r e h d n u la — 4; (V) Cdch 2: Dung mdy tinh cam tay casio 570es Z i = Z, i , Z e = - Z ( _ i Cai dat tinh toan vai so phuc mdy tinh casino fx-570es ( v o l i la s o a o ) + B A M [ M O D E | g ( D e c a i dat t i n h t o a n v i s o p h u c ) ' Dong dien i = IQ cos(iut + (P| ) i = I(,Zcpi + B A M ^ H T F T [ ^ D E | g §](De Di^n u = U(, cos (cot + cp^,) u = UoZcp, + '' B A M ^ H T F T | ^ D E | Q ( D e c a i dat d o n v i goc l a r a d ) Dinh ap luat 6m , U ^ I = — nhiina Z cai dat h i ^ n t h i so p h u c d a n g A Z (p) Z = 50V2(O) u u i =A — Z Z = R + i ( Z L - Z c ) = 50 + ( 0 - ) = Z - « ^ • I-'MN - '^un Z M N U = I Z nhi/ng > 11 7^ i Z Z M N Z U M N = I Z ^ N n/if/n^ " M N ' ' Z M N LIMN R+i ( Z L - Z c ) 50 + ( 0 - ) = ^Z^N u " y " M N 200Z- UoZcp, u = iZ = g'^MN = 2N/2COS 1007lt + n 12 (A) =272Z-^ 12 71 •V Cty T/SHHnrvDVVHKhang B6 trg klS'n thiic V$t li LTOH tren henh H i e n t h i tren m a n h i n h Thao tac CMPLX [5^R[ENGl0plOOlR^[)]R| SHIFT I ^ ^ R R Math 4) UcL = l^CL - - S - ^ C L 50 + i ( 0 - ) i i.'.A''' •.'•lA^ ^ 50V2Z-7r CMPLX SHIFT (-) SHIFT xlC* V • • • J.i;;^"j, y iim^Jt^.* • ' v •fM > + A n s SHIFT 1213 = R Math 200Z-^Ans • =220cos lOOTtt- 12 (V) cuon thuan cam c6 cam khang Z L = 25r} va t u dien c6 d u n g khang ZQ = H i e n t h i tren m a n h i n h Thao tac UQI - 220^/2Z ^^ (0 + 1(50-100)) =220Z —, 50 + 1(50-100) 12 v i d u 3: M o t mach dien xoay chieu mac noi tie'p g o m dien tro t h u a n R = 15Q, T o n g t r a la 50 \/2 Q va d i e n ap som pha hon d o n g dien la n/4 200 ' lOO N e u d o n g dien qua mach c6 bieu thuc = V2 cos(100Tit + 7t/6) ( A ) t h i bleu thuc dien ap gii>a hai dau doan mach la A u = 60cos(l OOKt + 571/12) (V) B u = 30 V2 cos(1007it + 7i/4) (V) C u = 60cos(1007rt - 7i/4) (V) D u = 30 N/2 cos(1007rt - 57r/12) (V) 2^/2Z — TC 12 Huong dan u = i.Z = V Z - ] x ( l + i ( - ) ) = 60Z — 6y 12 Bieu thi'fc d o n g dien i = 272 cos 100Trt + — ( A ) 12 V i d u : Dat dien ap xoay chieu u = 220^/2 cos(1007it + n/3) (V) vao hai dau "doan mach theo d i i n g t h i i t u g o m dien tro thuan R = 50Q, tu dien c6 dien d u n g C = 100/7i()j,F) va cuon cam thuan c6 t u cam L = 0,5/7r(H) mac noi tie'p 1) T i n h tong t r o ciia mach D i e n ap giiia hai dau doan mach som hay tre pha h o n d o n g dien mach bao nhieu? 3) Viet bieu thuc dien ap hai dau chua R va C 4) Viet bieu t h i i c dien ap hai dau chua C va L v; i, J"''?!' Huong dan v " ' Bam Tren Bam Z = 50V2(Q) 7t 2j~ SHIFT man hinh (-) y ( |15|| + ||ENG| ( 25 272Z30 x (15 +1(25 - ) ) '~Z = , Z ^ 12 • ~ R+ i ( Z L - Z c ) "50 + i(50-100) i = , cos lOOTCt- 7K 12 (A) ' Z : ^ ( 50+ 1(50-100)^ U R C = 491,935cos(1007rt + 0,725)(V) { |2N/2||SHIFT1[(-) 30[xj ( |15||+||ENG| ( [ j y [ l j ) ) 1H ISHIFTI [(+)J R se dUdc UQ = 60 Bam |SHIFT| se dMc cp^, = 75 V i d u 4: M o t doan mach d i e n xoay chieu noi tie'p theo d i i n g t h u t u g o m cuon cam t h u a n L c6 cam khang 30Q, dien t r o R = 30Q v a t u d i e n C c6 d u n g khang 60Q D o n g qua mach c6 bieu thuc = V2 cos(1007it + nl6) ( A ) Viet bieu t h u c d i e n ap glQ-a hai d a u doan mach chiia LR B U L R = 60^/2 cos(100Kt + 57r/12)(V) C U L R = 60V2cos(1007rt-7t/3)(V) D U L R = 60 >/2 cos(1007it + 7r/3) (V) Huang dan " L R 220N/2Z3 ) U R C = iZRc = " Z R C = ' 10 ) ) A U L R = 60cos(1007ct + 57r/12)(V) 220>/2Z- UoZcpu (V) 60Z75 Bam T i n h t o n g t r o ciia mach la 50 yfl Q; dien ap tre h o n d o n g d i e n la 7i/4 _ 12 Fx - M S : Z L =coL = ( Q ) ; Z e = — = 100(Q) o\ _ 5TC FX-570ES: t ^, •.^.'''r'' ) Z = R + i ( Z L - Z c ) = 50 + i (50 -100) = 5072Z - < > = u = 60cos 1007lt + => Chon A 2) Viet bieu t h i i c cua c u o n g d o n g dien tiic t h o i qua doan mach ^ Vift VTV2 tap - Chu VSn Bien + UO - 0 ) ) « 491,935Z0,725 ^ ' 11*' r = I-ZLR = 5% ^ V Z - X ( + ( - O)) = Z 6J 12 = > U L R =60COS So07rt + — ( V ) 12 Chon A ' 39 Cty Bo trg kicn thiic V^t IILTDII Fx - E S : Bam trcn Renh %rrV2 t^p - Chu VSn Bl£a > SHIFT ( - ) 30 ENG 30 D i e n ap hai d a u doan mach u = V2 coslOOTit (V) Viet bleu thuc d o n g d i e n qua mach va t i n h dien ap hieu d u n g 30 60Z75 Fx - 570MS: SHIFT ( - ) 30 Bam 30 ENG I SHIFT I [(+)| [=] se duac C/,„ ^ = 60 Bam Bam ' ' •' i'Sjii: ' i t i r f f u-:il?1'">''\,'i~;' £>''::i.iij -liii'ttK ' N ' M rT:"ji:1:vft'io;:; •'•] 'iiS'': [SHIFT | y se (fu^tfc cp^^ B i = 2N/2 cos(]OOTit + n/4) ( A ) va URL2 = (V) C i = 4.cos(1007tt - 71/6) ( A ) va U R L J = =75 tren d o a n mach la 440 W Bieu thuc c u o n g d o n g dien qua doan mach la B i = V2 cos(100Trt + 7i/4) ( A ) C i = 4cos(1007rt + K / ) ( A ) D i = N/2 cos(1007tt - 7i/4) ( A ) Huang dan y-'- U-R p = rR = •440 = 220\55 55^ + Zc : ,•••/'/2 cos(1007it + 7r/6) ( V ) C u^d = 200 N/2 cos(1007tt + n/6) ( V ) D u ^ = 100 ^/2 cos(1007ct + 7:/12) ( V ) , •g/vju Huang [ Z , = c o L = 100(Q) Zc = coC r^^,,i(2^_2^) ^ Vi - Z = R + i(ZL-Zc) =30(Q) z _ u_ = Z - - : » i = 4cos lOOnt ' " Z ~ + i ( + 30) I I6OV2 U K L = I-ZRL2 = 2V2.5O = 100V2 ( V ) 71 — (A) Chon D ^ V i d u 8: Cho mach dien xoay chieu gom dien tro thuan R , cuon day thuan cam mac noi tiep Neu bieu thuc ciia d i e n ap giCra hai cos(1007Tt - 37T/4) ( V ) t h i bieu t h i i c ciia c u o n g d o n g dien t r o n g mach la ^ ' i ^ ^ ' ^ ' - ' ^ " ^ f-^-' A i = V2 cos(1007rt + 37r/4) ( A ) B i = x/2 cos(1007:t) ( A ) , C i = 5N/2cos(1007rt-7r/4)(A) D i = 5cos(100Trt - 37i/4) ( A ) - ! Huang dan =J-.IOQ (oC u 50^/2Z-^^ =>i = ^ = ^ = 5x/2Z 7r Z + i(0-10) Z = + i(0-Zc) lOOTlt (A)=>ChonC V i du 9: M o t doan m a c h xoay chieu noi tiep A B g o m d i e n t r o lOOQ, cuon cam t h o i gii>a hai d a u cuon cam c6 bieu thiic ui = 100cos(1007Tt - 7T/6) (V) (t b a n g giay) Bieu thuc d i e n ap hai dau doan mach A B la 200N/2Z-~ 200-j2Z~n 1007tt + - 12 A u = 100 V2 cos(1007rt - 1171/12) (V) B u = 100 V2 cos(1007tt + ll7t/12) (V) C u = 50cos(1007it + 7t/12) (V) D u = 50 N/2 cos(1007tt + 7t/12) (V) ( V ) => Chon A Huang du 7: Cho d o a n mach xoay chieu noi tiep theo d u n g t h u t u g o m cuon cam t h u a n CO d o t u cam L i = 0,1/?: ( H ) , d i e n t r o t h u a n 40 Q va cuon cam t h u a n C O t u cam L2 = 0,3/71 ( H ) /in =10(Q) t h u a n CO cam khang lOOQ va tu dien c6 d u n g khang 200Q Biet dien ap tuc X (lOoVs + i.lOO) = u^H = 200V2cos =COLI i = 5V2icos dan = 200(Q) Z-H = r + iZ ^_ dan =«L2 ZL, Zr t h o i tren cuon day la ti ; L va tu d i e n C = 1/n mF " Z " 55+1(0-55) Vi [ ban t u dien la Uc = 50%/2 22072 u ,.j;f^ (V) Huong g o m d i e n t r o t h u a n R = 55Q mac noi tiep v o i tu dien t h i cong sua't tieu thu = 4cos(1007tt-7t/4) ( A ) (V) D i = 4cos(1007it - 7C/4) ( A ) va U ^ L J = 100 V ( V ) ) ) 30 V i du 5: D a t dien ap xoay chieu u = 220 ^/2 coslOOTit (V) vao hai d a u d o a n mach A.i tren doan mach chua RL2 A i = 2N/2cos(1007it + t / ) ( A ) v a U i^^^ = WO %/2Z30x(30 + i ( - ) ) Trenmanhinh y/ft TnmnnrvDVVHKltang u = iZ = ^ Z ZL = dan _ _ x (100 + 1(100-200)) = 100^y2Z lOOi ^ ^ r, 12 41 Cty TiyHHMTVDVVnKhang V^t li LTDH tren k&nh VTV2, t^p - Chu TTTT ( V ) = > C h o n A u = 100N/2COS l O O n t 12 ) Bo trffhicn thiic VHn Bien VIft V i d u : M o t doan mach xoay chieu gom dien t r a thuan R mac noi tiep h o p kin X H o p k i n X hoac la tu dien hoac cuon cam thuan hoac d i e n t r a thuan Biet V I d u 10: M o t doan mach xoay chieu no'i tiep A B theo d u n g thu" tir g o m dien t r o R = 25N/3 il, cuon cam thuan L c6 cam ir'' 60Z- ' A 30 Q va l/(3n) m F - ' j' Viet lai bieu thuc: i = 2sin(1007it + it/6) (A) = 2cos(1007it - 7r/3) ( A ) Z = R + i(ZL-Zc) = - = gii>a hai dau doan mcich va d o n g dien mach Ian l u g t la: ^^^^ ,,„ ' Q va P = 30 ( W ) 0,6/K ( H ) , d i e n t r a t h u a n R va tu d i e n c6 dien d u n g C Biet bieu thiic d i e n ap Gia t r i cua R va C Ian l u g t la ; Huong dan Vi d u 1: M o t doan mach xoay chieu no'i tiep g o m cuon cam t h u a n c6 d o t u cam ,, , i, : , ; ( O t + Cp^i ) M a t k h a c : Z = -= , • > 10 -3 • (F) 3n ,,, =>ChonD ap xoay chieu u = 0 c o s ( 0 K t + TI/6) i = c o s ( 0 i t + 271/3) ( A ) thuc u = i = 72 400-72 (V) thi cuong d o n g d i e n qua mach N e u thay dien ap tren bang d i e n ap khac c6 c o s ( 0 r t + 7i/3) (V) thi cuong dg bieu dong dien: c o s ( 0 r t - 7i/6) ( A ) X c6 t h e c h i i a A R = ( Q ) , L = , / i ( H ) , C = 10-*/7t ( F ) B L = 0,7/71 ( H ) , C = 10-3/(1271) ( F ) ' 43 Bo trp hien tiluc C L = 1,5/7T D R = V^l li L TP 11 tren kcnh VTV2 t4p2-Chu V0n Cty TlSnn MTV D VVH Khang Blin Huong (H), C = l,5.10"V7t (F) (Q), L = / (H) •^"'•'f! n v * y ! st.o:' >, 20o72z^'' ^ UAM ^ ^ ZAM lOOZ" R = Z =R +i (ZL - Zc) =- = = - i => , 2^ ' 2Z ^ TSMi!'.4.', A, Z =R+ 2ZL u/"°^-^3 = 80i: Z, =70(Q) 0,7 L = IOOT: = 80 Zc =120(Q) r-u T3 • c = —.IO^VF) •••"^ -.'> cuon day la: B.25a ' ' C 50 Q Huong i,?,' , •,;>;.v/i^v B Dien ap giua hai dau doan mcich A B tre pha TI:/6 SO v o i dien ap giija hai „ d o n g d i e n qua mach c6 dang i = 2cos(100Trt - 7r/3) (A) D i e n t r o thuan cua Q •^ A C u o n day CO dien t r o r khac • V i d y 5: D i e n ap a dau cuon day c6 dang u = lOOcoslOOTit (V) va cirong d o 72 « / v n ' i - ) i o r t (•/, K e U u a n nao k h o n g dung? 12% A.25 • H.nLuri;: Chon A ' ' l u i ' r I t ' i (Si ' ( ' « ' i , , (, , U K = 120cosl007rt (V) va u^^ = 120cos(100Tct + K/3) (V) (H) t ^ r = 125(Q) Biet dien ap giua hai dau dien tro va hai dau cuon day Ian l u g t la 2Z, »P V i d u 7: M o t doan mach A B gom dien t r o R mac noi tiep v o i cuon day xi' • i\'-Ai - 5072Z Thuc hien cac thao tac bam may tinh [=] bllilil dJ x(40-40i) -7K 12' J d u o c ket qua EE cos 0,84 nghia la coscp « 0,84 => Chon B doan mach X Dat vao dau mach m o t dien ap u = 120N/2 cosl007:t (V) t h i c u o n g d o n g dien qua cuon day la i = 0,6 V2 cos(1007:t - 71/6) ( A ) T i m hieu (50 + i ) dien ap hieu d u n g giua dau doan mach X A V 200Z- B.120N/3V C.60^/2V D.120V Huong dim ux = u - U L = u - I Z L = 120>y2 - ( , V Z ~ 30)200i = 120^y2Z - 60 N e l l b a m p h i m ' = ' ta d u o c ki^'t qua: 67,68 + 19,381 RAB= - A M - A M Sau k h i nhap vao m a y t i n h so'lieu n h u tren: Tir ket qua ta suy ra: 150 I^MB V i du 11: C u o n day t h u a n cam co he so t u cam L = 2/71 (H) mac n o i tiep v o i dan T o n g tro p h u c toan mach: ZAB ( " A M + ^ M B ) " A M A M va M B Ian l u g t la UA.\ = 200cos(100Tit + TI/6) (V) va UMH = 100cos(1007Tt 57T/12) ( V ) H o i tren A B tong cam khang nhieu h o n hay it h o n tong d u n g dan = 40(Q) Zr = thuan R i = 50 (Q) mac noi tiep Doan mach N B g o m tu dien co dien d u n g C 67,68Q va Z , ( ^ B ) " ZC(AB)= 19,38Q (tong r:>Ux = ( V ) = ^ C h o n D cam khang nhieu h o n tong d u n g khang la 19,38 Q) Z^B = 70,4Q va cpAi? = 0,279 rad (Dien ap UAB som pha h o n i la 0,279 rad) Phuangphdpgidi He so cong suat cua mach A B : coscpAu = cos0,279 = 0,96 '"' Co the t i n h true tiep coscpAis bang may t i n h casio fx570es t u ket qua: 12 1+ (50 + 50i) ^ ^ 1) D i e u kien cong h u a n g Z , Z c « L o ~ « c o =^ f = VLC 271 O T = 27IVLC I»U coC Bam p h i m ' = ' 21=' o Z z , = I Z c o S L c = S-i 200Z ^ Bam 'shift BAi TOAN LIEN QUAN DEN CQNG Hl/dNG DI^N VA DIEU KlfN LECH PHA Neu bam p h i m 'shift =' ta d u o c ket qua: 70,4Z0,279 T u ket qua ta suy ra: Vl^t ==>p I (de lay goc 'iii.ix - , =r- 'cong_luH)ng 'max R = — * t''«' R H e qua cua hien t u o n g : cpAis) Bam 'cos =' se d u o c ket qua 0,96 (tuc la cos(pAB= 0,96) tan cp = =>(p = ne n u = U R , i : cung pha : V i du 10: (DH-2011) Doan mach A B g o m hai doan mach A M va M B mac n o i tiep Doan mach A M g o m dien t r o thuan R i = 40 Q mac noi tiep v o i tu dien CO dien d u n g C = 0,25/:: mF, doan mach M B g o m d i e n t r o t h u a n R2 mac noi hai d a u doan mach m o t hieu dien the xoay chieu co tan so thay d o i K h i tiep v o i cuon cam thuan Dat vao A , B dien ap xoay chieu co gia t r i hieu tan so goc cua d o n g d i e n bang COQ t h i cam khang va d u n g k h a n g co gia t r i 20 d u n g va tan so k h o n g d o i t h i dien ap tuc thoi hai dau doan mach A M va • V i du 1: Cho d o a n mach R L C n o i tiep co gia t r i cac p h a n t u co d i n h Dat vao Q va 80 Q De t r o n g mach xay cong h u o n g , phai thay d o i tan so goc cua M B Ian l u o t la : UAM = 50 V2 COS(1 OOnt - 7Tr/l 2) V va UMB = ISOcoslOOnt (V) d o n g d i e n den gia t r i CO bang H e so cong suat cua doan mach A B la A A 0,86 B.0,84 0.0,95 D 0,71 COg B 0,25 COQ C 0,5 COQ D 4coo thUc V$t It LTDII trphtSn Ht'ni hcnh C t r Tiyilll MTV D VVn VTV2, t^p - Chu VMii isk-ri Huong dan Z[ =W(,L (i)C = 20(a) j^hi f = f, t h i Z L = Z L , 20 L= - >Z|, ^50- + 2,25.Zr, =• hay V - • • • 0,8 = 80(Q)=>C = =^ vaZ,=VR^.(Z,,-Zc,)^=^ Chon A =25(Q) 1 I /20 ,v 'y ,„ tiep v o i tu dien c6 dien d u n g SOO/TI ().iF) Dat vao hai dau doan mach mot dien ap xoay chieu tan so 50 (Hz) De d o n g dien t r o n g mach cung pha v o i dien ap ta phai ghep noi tiep v o i tu C m o t tu C i c6 d i e n d u n g la bao nhieu? B 250/Tt (laF) doan mach M B g o m dien tro thuan R2 mac no'i tiep v o i cuon cam thuan c6 tu cam L Dat dien ap xoay chieu u = Uocoscat (Uo va co k h o n g doi) vao hai V i d u 2: M o t cuon day c6 dien t r o thuan 100 (Q) va c6 d o t u cam l/n ( H ) , noi C 125/7t (^iF) dau doan mach A B t h i cong sua't tieu thu cua doan mach A B la 85 W K h i LCCO^ = va lech pha giira UAM va UMB la 90" N e u dat dien ap tren vao hai dau doan mach M B thi doan mach tieu thu cong sua't bang: C B 135 W D 50/7t (^iF) , = Z, => — + c n o w A/ U) = coL => C, = — ( i - i F ) => Chon C va bien t r o R mac noi tiep K h i dat vao hai dau mach m o t dien ap xoay Z,,=Zc=^P = Dat dien ap vao A B : chieu on d j n h c6 tan so'f thi thay An^i'^hC = K h i thay d o i R t h i ^, :i , , , , , Tir dieu kien T I ^ F L C = suy Z L =ZQ, P' = R2 = U'R R; + Hu6iig dan tuc la t r o n g mach xay cong < =-1 -Zc ZL = - ^ Z L =RiR2 zi U-R, R2 + R , R Ri + R2 = P = ( W ) = ^ C h o n A A day Dat vao hai dau doan mach mot dien ap u = U V2 coscot (V) t h i d i e n ap hai dau t u d i e n C la u ^ = U N/2 cos(a)t - 7t/3) ( V ) T y so gii>a d u n g k h a n g va • Chon C P thay doi uc Mat khdc ui sani han i la KI2 va uc tre han i la TT/I ; tie suy (p V i d u 6: M o t mach d i e n xoay chieu g o m m o t t u d i e n C n o i tiep v o i m o t cuon ^7 I -y Z = R ' + ( Z | - Z e f = R => Z thay doi cam k h a n g bang A 1/3 R B 1/2 R = 50Q K h i xay cong h u o n g d tan so'fi t h i c u o n g d o n g d i f n bang A V i I l u o n luon som han mach la 0,8 A C a m k h a n g cua cuon day tan so f i la C 37,5 Q D 75 Q - la n/2 va theo bai U s o m h a n UQ la n/3 nen ^ tre pha h a n I la 71/6, tuc la (p = - — C h i tang tan so cua mach dien len gap doi t h i c u o n g hieu d u n g t r o n g K h i f = f, t h i Z c , = Z L J va U = U K = I j R = 50 ( V ) D.2 x^^^^m Huang dan V i d\ 4: D o a n mach xoay chieu RLC mac noi tiep, d i e n t r o thuan cua mach Huo^tg dan -• C cos(p = — = = khong doi VR • 48 -(Ijf Chu y: Neii cho bicii thuc u, ui hoac uc ta dnh dime lech pha cua u vai UL hoac 'U,^ = U = khong doi VR B.50Q v > J III Dat dien ap vao M B : D he so cong suat tren mach thay d o i A.25Q , , C cong suat tieu t h u tren mach thay d o i R ' R, + R t a n t p A M tancp^B B tong t r o cua mach van k h o n g d o i P=- , Huong dan V i d u 3: Cho doan mach d i e n xoay chieu g o m cuon day t h u a n cam L, tu dien C A dien ap hieu d u n g gii>a hai dau bien tro thay d o i ^n^, A.85W D 170 W h i r a n g va l i i c : «• -,1 ,),v'.R R = (Z, ZL)>/3>0 V e L/ D u a vao bieu thuc u va uc suy ra: U A B = 4R ^ + ( Z L -Zcf =Zc ^AB = ^^Y = > ( Z c - Z L ) = Zc=>Zc=2ZL=>ChonD 49 tri? Men V$t li LTDH tren htinli thitc Vli2 J - Chu l.,p VSn Cty BlSa i du 7: Mot doan mach xoay chieu noi tiep AB gom dien tro thuan R, cupn cam thuan L va tu dien c6 dien dung C Dien ap giiia hai dau doan AB la: u = Uo>/2 coscot (V) thi dien ap tren L la U L = Uo N/2 cos(cot + 7t/3) (V) Muon mach xay cong huang thi dien dung ciia tu bang D 2C C0,5C ' Huang dan Vi luon luon tre pha han f/, la n/2 va theo bai U tre pha han U^^ la n/3 A.C^ B 0,750 tancp = ^i^—5^ = t a n - ^ R = ( Z L - Z c ) V3 > R {/L lech pha vdi De xay CQng huang thi _ — = i — C = - C => Chen B (oC 3coC ^ i du 8: Mot doan mach noi tiep gom cuon cam thuan, tu dien va dien tro R Dat vao hai dau doan mach dien ap xoay chieu c6 gia tri hieu dung 120V thi cam khang cuon cam la 25Q va dung khang cua tu la lOOQ Ne'u chi tang tan so dong dien len hai Ian thi dien ap hieu dung giiia hai dau dien tro R la A V B 120 V C 240 V D 60 V • Humgdan I d Z'c = Z L = > Z ' C Z'L =a)L ZL =COL = ( Q ) (i)'=2(o Z c = - ^ = 100(Q) Zc = (oC pi = 50(Q) pha vdi dong dien I Cling • Cong hiCcfng • la — =6,25—= 6,25a)L = 6,25Z[ Z^ =6,25ZL C coC ^ ffq.p;^< V/ft Huong dan t/| sdm pha h0n dong dien I la — =^ Z L = 2.2(ZL - Z C ) => Z L Khang V i dv 10: Mot doan mach AB mac noi tiep gom: dien tro thuan R, tu dien c6 dien dung C va cuon cam thuan c6 tu cam L thay doi dugc Dat vao hai dau doan mach AB dien ap xoay chieu 100 V - 50 Hz Dieu chinh L de R = 6,25L/C va dien ap hai dau cuon cam lech pha so voi dien ap o hai dau doan mach AB goc n/2 Dien ap hieu dung a hai dau cuon cam la A.40(V) B 30(V) C.50(V) D 20 (V) nen U som pha hon / la TC/6, tiic la c = — p U L = U A B =^ Z L = ^/2^/R + ( Z L - Zcr Tjyftlf JVTVDVV/f =>Z^ t oil rvvf- =0,4R =^ U L = 0,4UR = ( V ) => Chon A Chu y: Tir dieu kien cong huang de tinh cdc dien dp, ta van dung cdc cong thu sau : , T2 L,R J =0 U^c = C + U ^ ; U ' = ( U R + U,f + (UL^UC)' U?, = U ^ u f , ; U ^ , e = U ^ ( U , , - U c f R ^ C » i l l \il-J> - j , ^ ; J / J = 50(Q) V i du 11: Mach gom cuon cam va tu dien c6 dien dung thay doi dugc mac noi Xay cong hudng => UR = U = 120(V) => Chon B Z',=Zc du 9: Mot doan mach noi tiep gom cuon cam thuan, tu dien va dien tro R chinh dien dung de mach cong huang, liic hieu dien the hieu dung Dat vao hai dau doan mach dien ap xoay chieu c6 gia tri hieu dung U thi dau cuon cam hang 200 (V) Khi hieu dien the hieu dung giCra ban hi la dung khang gap bon Ian cam khang Neu chi tang tan so'dong dien k Ian thi dien ap hieu dung giiJa hai dau dien tro R la U Gia tri k bang A 0,5 B.2 C.4 ^ Huong dm Z r =4ZT coC -4coL=^LC- CO" 4(0 = nL/C thi 100 V3 (V) ' T2 U, =Ur j\ f f -=>LC- (0 = nZj^Zc vd Ua' = HULUC • 200 (V) T,2 /TT = + (UL Uld = 4(0^ (o'C B C 100 (V) D 100 V2 (V) Humgdan D.0,25 • co' = 2(0 => Chon B CM y: Neu cho Met A U R = U => Xay cong hicdng => co'L • • tiep roi mac vao nguon xoay chieu u = 100 V2 coscot (V), co khong doi Dieu + IT - U c \ ^ T TUR =TUT =^ 100 f => 200^ = 100^ + ''^ M Ji'A LV^iH %St^i ii ' J • ' =^ Uc = lOoVs (V) => Chon A V i du 12: Doan mach xoay chieu noi tiep gom dien tra thuan R, hi dien C va cuon cam Lr Dat vao hai dau doan mach mot dien ap xoay chieu 120V - 50Hz thi dien ap giira hai dau doan R-C va dien ap giira dau doan C-Lr va co Cling mot gia tri hieu dung 90 V va mach dang co cong huang dien Dien ap hieu dung gifra hai dau tu dien la A.30>^V B.60V2V C.30V3V D.30V B d t r p klS'n thiic V^t II L T B t l t r i n kenh VTV2 t^p - Chu V^n Blen Huong dan UL = UC U K + U , =120 U2=(UK+U,)'+(UL-UC)'=1202 Uf^ + U c = U r + ( U L - U c ) Si I" Ci coL, U, =90^ +CDL2 = -7r- + 1 + «2C2J V Chon B Uc = V ( V ) • • ' viiH mach dcS vc7i m p t mach t h i no se cong h u o n g voi d o n g d i ^ n xoay chieu CO tan so g o c l a C/iii y; Tin' y; tn CQn C„ > — ( M F ) nen I tang roi giam => Chon D ^ • co^4L| =co^L, +4co^.3L| =^ co = 0,5cO()>/i3 => Chon D X, :})'T ] 100 K h i mach cong h u o n g : wL = — = > € „ = — - = (f.iF) 7t coL| + CO 1.2 = B tang ' 2co?Ci ^^"i^^/ ' , C, • +— • CO = coiV2 , V i dy 16: H a i doan mach noi tiep RLC khac deu cong h u o n g v o i dong (oLj + (0L2 = (L, + L ) = co?L, +co^L2 coCj + •Mf'/ dien xoay chieu c6 tan so f N e u mac noi tiep hai doan mach d o vc?i a)C2 < = • mt)t mach t h i no se cong h u o n g v o i d o n g d i ^ n xoay chieu c6 tan so la • 0)iL|Ci = => L j = - 21 A f B l,5f C.2f D.3f Huong dan Ca hai doan mach ci:mg cc)ng h u o n g v o i tan so f nen k h i ghep n o i tiep Neil cho lien he C thi khu L: ) L C = => L = CofC2 c h u n g C L i n g cong h u o n g v o i tan so'f Chon A j 53 - Botrpkien thitc V^t li LTDH tren henli VTV2 t^p Chu Van Bien 2) D i e u ki#n I^ch pha * Tren doan mach k h o n g phan n h a n h chi chua cac p h a n t u R, L va C Gia sir M , N , P va Q la cac d i e m tren doan mach D o lech pha ciia \Xy^^, u p g so Huong •IPP' tancpAM - R ZL v6i d o n g dien Ian l u g t la: tancp^^fj = ^^^^ va tancppQ = ^'"^ dan f t ' ' : IOOV3 - Zc _ ZL - 200 tancpAB=—100V3 , , , , Vi d i e n a p giira hai d a u d o a n m a c h A M v a d i e n ap g i i i a h a i d a u d o a n m a c h * UMN k h i va UpQ chi tancpMN tancppQ = - ^ PQ ^ _ ^ AB lech p h a n h a u 71/6 n e n s u y cp^^ - cp^H = - V i du : (DH-2010) M o t doan mach A B g o m hai doan mach A M va M B mac noi tiep D o a n mach A M c6 dien tro thuan 50 Q mac n o i tiep v a i cuon cam Cdch 1: thuan CO t u cam I / K ( H ) , doan mach M B chi c6 t u dien v o i dien d u n g D i e u chinh dien d u n g ciia tu dien den gia trj Cj cho dien ap giua hai dau doan mach A B lech pha 7i/2 so v o i dien ap giira hai dau doan mach A M Gia t r i ciia Ci bang B.80/7r(nF) A 40/71 (laF) C 20/7i (^F) Huang dan Z L = c o L = 100(n) ,r Xlfiu'l, , , V i u U A M nen: , ZL-ZC t a n c p t a n m v i = - => — D 10/7i(^F) v Zc =125(Q)=>C = ^ — = -.10"^(F)=>ChonB i ^ 300 ^ 0 ^ tancpAM- ^ - ^ 0 ^ tan cpAB = ZL-ZC _ZL-200_ = = R Huong tan (PRI tan (PRC = - => Chu y: Ncu thi tan ((p2 D 120 Q A 0 ( - V ) Q h o a c l 0 V Q = B.IOOQ C lOOVSQ D 0 Q h o a c l 0 N / a r mach A M va M B mac noi tiep Doan A M g o m dien t r o thuan R = 100>y3 Q mac noi tiep v o i cuon cam thuan c6 cam khang Zi., doan M B chi c6 t u dien CO d u n g k h a n g 200Q Biet dien ap giCra hai dau doan mach A M va dien ap giij-a hai d a u doan mach A B lech pha 7c/6 Gia trj Zi bang D 300 Q ' Huang dan Cdchl: Zc = — = 200(0); coC 57t 12 tan (pAM = '' ZL /•I ~R ' ~ Too Z, - Z r tancpAB =R tan(p(,£] - tancp 571 I = tan1 + tan (Pcd tan (p 12 = tan ^^P C.IOOVSQ - 'PAB cpAB- : rt'i'Ji''"*'' Z L -200 •' ^ '^ " 100 •••^iiacn.l.srcy^* f ^ i - ^ A I'Jr ZL-200 ZL 100 100 100• -^>^) = V i du 3; Dat dien ap xoay chieu vao hai dau doan mach A B g o m hai doan B lOOQ 9AM 300-200 - khang ciia cuon day bang dan + tancpj tan(pi A.50V3Q hai dau cuon day va dien ap giiia hai dau doan mach la 57i/12 thi cam 50 50 ,H iofi i-^f/ • — ^ = - => R = J — = 200 (Q) => Chon B - cp, = A(p 71 noi tiep vol tu dien c6 dung khang 200 Q Ne'u lech pha cua dien ap giiia dien ap hai d a u doan chua RC t h i R bang C 300 Q mi | , d u n g C = 0,l/(7r) (mF) Ne'u dien ap hai dau doan chua RL v u o n g pha v a i B 200 Q Chon D Cdch 2: T h u p h u o n g an ta nhan thay chi p h u o n g an D la d u n g , cam thuan c6 t u cam L = 4/K ( H ) , dien t r o thuan R va tu dien c6 dien , ^ = -1 V i du 2: Cho doan mach xoay chieu mac no'i tiep theo d i i n g t h u t u g o m cuon A 30 Q V i du 4: M o t doan mach dien xoay chieu gom cuon day c6 dien tro 100 Q mac 0 - Z c 100 ^ = - => 71 tancpAM - t a n t p A B _ • ''^ 200.100N/3 • = tan — => l + tancpAMtancpAB (lOOVs )^ + Z ^ - 0 Z L Z L - 200ZL - 30000 = => Z L = 300(Q) thay d o i duoc D a t dien ap u = UocoslOOrct (V) vao hai dau doan mach A B >1v|.;i!:;M'J:>»TS.':t';yrii • zl - 200ZL + 10000 (2V3 - ) = 100 Z L =100V3(Q) ZL = 0 ( - ) ( Q ) ' • Chon A ^dch 2: K h i d i t h i ne'u l a m theo each se mat nhieu t h o i gian de giai p h u o n g t r i n h bac 2! De khac phuc kho k h a n ta d i i n g p h u o n g phap t h u true tiep bo'n p h u o n g an Buoc 1: Voi Z L = 100 Q t h i cpAM = 7t/4 va cpMB = -7t/4 => k h o n g d u n g 55 Bd trp kiSn tbiic V$t It LTOHtri 11 J ,i h d i i n g Buoc 3: V o i Zi = 300 Q t h i k h o n g h o p l y D i e n ap xoay chieu hai dau mach chi tan so goc co thay d(>i ducjc Ta thay co Buoc 4: Ke't luan chon A , gia trj ciia co la co^ va CO2 t h i lech pha cua hieu dien thegiCra hai dau V i d u 5: Dat d i e n ap xoay chieu on d j n h vao hai dau doan mach mac no'i tiep doan mach v o i d o n g dien Ian l u g t la (pi va (p2 Cho biet cpi + 92 = n/4 C h o n he g o m cuon day co dien t r o thuan R, co cam k h a n g 150 Q va tu dien co dien thuc d u n g : d u n g C thay d o i dugc K h i d u n g khang Zc = 100 Q va Zc = 200 Q t h i dong A ( c o i + C ) R L = R _ d i e n t r o n g mach co pha ban dau h o n kem TC/3 D i e n t r o R bang C ( C O , + ( ) R L = R2 + o ) , ( L , A 50 V3 Q : • B 100 Q - C 100 V3 Q Huong Z, Zc, 50 Cdch 1: tancp, = / ^ ] + tan 50^50 v- dan ^ -50 tancp2 = D 50 D - tan — tan cp] R tancpj = (|)| =- R Z L - Z^^2 -50 R R (P2 n'.j^::h )bll ;|i ' R W2L => Chon A R=50V3(Q)=>Chon A = se bien d o i thenao? hoac RL vao d i e n ap n o i tren thi cuong d o n g dien tiic t h o i t r o n g hai t r u o n g h o p lech pha 27t/3 va co cijng gia t n hieu d u n g A K h i mac d o a n mach noi tiep R L C vao d i ^ n ap noi tren thi gia trj c u o n g d o d o n g dien hieu d u n g t r o n g mach la A A '\ B A Huong dan tanipi = tan R -Zr =• R Z i = Zc = R V U = I,ZK, = R ' + Z ^ =>] = u =4R u = — = ( A ) => Chon A V R ^ ( Z , - Z C ) ^ " R 56 D A C l A Ii = I , => ZRL = ZRP => Z , = Zr => RC R = 1- (0|L CO2L R • R Ami-11^^- , • „ ,, 2jt -V2 = ri ="C1 = -(|>2 ,5.) 1-">IS^; A I khong doi, lech pha k h o n g doi , yUuA^i rod? imt mli WM) ^ n l n B I giam V Ian, lech pha khong doi ;n oSv 'Ifi Huotigdan mi 'V'^'v •J&ui=! gno*) rttx'' :' R- coC Td/i/,' liva L len Ian va giam C Idn coLtan (p = • ' ,:Q,-fC>r*> D I va lech pha deu giam = ' - dsSm i-^tfe : I C I giam Ian, lech pha khong dcii t u d i e n C, cuon cam thuan L K h i mac Ian l u g t hai doan mach noi tiep RC , • N e u ta tang L va R len hai Ian, giam C d i hai Ian t h i I va dc) lech pha giua va :0, !i()f V i d u 6: Su d u n g m o t d i e n ap xoay chieu on d i n h va d u n g cu g o m d i e n t r o R, ? Huong dan d a n g CO gia trj I va d o n g dien / som pha n/3 so v o i dien ap ;( dat vao mach •/POX \vMh &-f,ni R D (co, + (02) R L = R^ - 2c,),co2 L^ V i d u 8: Cho mach gc^m tlien trci thuan R, tu dien C va cuon day thuan cam L ,.,,V 50 CO1CO2L2 mac no'i tiep VtVi cac gia t r i ban dau t h i c u o n g d o hieu d u n g t r o n g mach Cdch 2: tan R = 50^/3 ( n ) => Chon A R 'PI +i|>2 = " , R )'• a ; '' ''1 'tVi I' j , , , - jlf^.: , co^L R tancp, = L2 (oC = tan — = -^/3 R \\ Idn < , => Chon C Do lech pha khong doi Bo trfi kicn thiic V^t li LTDH tren hcnh VTV2, t^p - Chu VSn r Huang dan I ,M , li J, i.1 I >U : ,>) t 'I ' >i tan = Z, I - 3R R tan(p = ^ ^ P t = ^ = 1936 0) • Z„=2,5R I2 =0,51 = R 15 VJft (W) £)ien nang ma doan mach A B tieu thu t r o n g m o t p h i i t 7R'+(ZL,-3R)' VR^+(Z,-ZC)^ 484 (100 + 200)^ + ( 0 - S O O f (R + r f + ( Z L - Z C ) /2 coslOOnt (V) K h i U = 100 V thi cuang dong dien mach tre - na 1) H e so cong suat cua cuon day va cua doan mach A B Ian l u g t la 200 U' D.50W R 200 V i du 4: Cho doan mcich RLC, dat vao doan mach dien ap xoay chieu Z[ =coL = 200(Q) D u n g Ichang va cam k h a n g : C l O O W (W) 100 ^ tan(p=^'-"^^' R D.73,2Q dan 11 c a s ^ - = > R = 50(Q) ^ ^ = tan - => Z[ - Ze = RS = SoVs (Q) " f f f! u 59