chapter 18 18 23 java awt flowlayout jdk 1 0

... setFilenameFilter (FilenameFilter filter); 10 July 200 2 22:27 958 FILEDIALOGPEER java. lang.Object java. awt. Component java. awt. Container java. awt. Window java. awt. Dialog java. awt. FileDialog } Interface Methods ... index See Also Menu, MenuComponentPeer 23. 16 MenuComponentPeer java. lang.Object java. awt. MenuComponent java. awt. MenuBar java. awt. MenuItem 10 July 200 2 22:27 java. awt. io.Serializable 966 MENUCOMPONENTPEER ... { } See Also ContainerPeer 23. 20 10 July 200 2 22:27 PopupMenuPeer # SCROLLBARPEER java. lang.Object 969 java. awt. MenuComponent java. awt. MenuItem java. awt. Menu java. awt. PopupMenu Description PopupMenuPeer...

Ngày tải lên: 26/01/2014, 07:20

... Title of the Book, eMatter Edition Copyright © 200 4 O’Reilly & Associates, Inc All rights reserved 5 51 ,ch18.2 50 21 Page 552 Thursday, November 18 , 200 4 12 :44 PM To accomodate this, Apache maintains ... Title of the Book, eMatter Edition Copyright © 200 4 O’Reilly & Associates, Inc All rights reserved 553 ,ch18.2 50 21 Page 554 Thursday, November 18 , 200 4 12 :44 PM References • mod_include, an Apache ... ,ch18.2 50 21 Page 5 51 Thursday, November 18 , 200 4 12 :44 PM $RA_CACHE = get_data( ) unless $RA_CACHE; my $second = $RA_CACHE->[SECOND];...

Ngày tải lên: 20/10/2013, 09:15

Ngày tải lên: 20/10/2013, 17:15

... timeit.Timer("soundex.soundex('Pilgrim')", "import soundex") >>> t.timeit() 8. 216 83733547 >>> t.repeat(3, 200 000 0) [16 .48 319 30 9 10 9, 16 .4 612 8984 923, 16 .44 203 948 912 ] The timeit module defines one class, Timer, which takes ... C:\samples\soundex\stage1>python soundex1e.py Woo W 000 13 . 506 9 504 644 Pilgrim P426 18 . 219 939 405 7 Flingjingwaller F452 28.9975225 902 Example 18 . 3 Best Result So Far: soundex/stage1/soundex1e.py import string, re ... performs: C:\samples\soundex\stage1>python soundex1c.py Woo W 000 14 .53 416 789 01 Pilgrim P426 19 .26 500 714 48 Flingjingwaller F452 30 . 10 03 563 302 This code is straightforward, but is it the best solution?...

Ngày tải lên: 28/10/2013, 16:15

Ngày tải lên: 29/10/2013, 03:15

Ngày tải lên: 07/11/2013, 18:15

... trống C/ Củng cố dặn dò: Nhận xét học 46 12 thừa số thừa số tích 10 18 20 14 10 16 2 2 10 10 14 18 20 2 Tuần thứ 20 Thứ hai ngày tháng năm 200 6 Chào cờ Tiết 20 : tập trung toàn trờng Tập đọc : Tiết ... bảng 35 84 40 10 0 35 26 60 75 70 58 10 0 25 em đọc yêu cầu 14 - + = 15 15 - + = 12 + - =6 11 - - = 12 em đọc yêu cầu a)Lấy tổng trừ số hạng biết SH 32 12 25 50 SH 50 25 35 Tổng 40 62 50 85 - Nêu ... hành Bài 1: Tính Học sinh nêu cách cộng 12 15 34 46 40 29 86 98 - Học sinh nêu miệng + + = 14 + + = 20 + + = 18 + + + 6= 20 - Học sinh làm vào bảng 14 36 15 24 33 20 15 24 21 15 24 15 24 60 96 Bài...

Ngày tải lên: 25/11/2013, 22:11

... ClO3 -1 + Cl -1 → Cl2 (in acid) +5 -2 -1 reduction ox: red: tot oxidation Cl -1 → Cl2 + e -1 } x5 ClO3 -1 + 10 e -1 + 12 H+ → Cl2 + H2O} x1 10 Cl -1 + ClO3 -1 + 12 H+ → Cl2 + H2O ClO3 -1 + Cl -1 + H +1 → ... Burdge, 2nd e., McGraw Hill 10 Common Oxidizing Agents Oxidizing Agent Product when Reduced -2 O2 O H2O2 H2O -1 F2, Cl2, Br2, I2 -1 -1 -1 -1 F , Cl , Br , I -1 -1 -1 -1 -1 ClO3 (BrO3 , IO3 ) Cl , ... + e−2→ He − log K = ( − 0. 34 V ) = 11 .5 0. 0592 2+ V + tot: Cu(s) + 2H (aq) → Cu (aq) + H2(g) E° = 0. 34 v K = 10 11 .5 = 3.2 10 12 Answer: since Κ < 1, the position of equilibrium lies far...

Ngày tải lên: 28/11/2013, 01:12

... process (chapter 5) Decision making (chapter 6) Human resource management (chapter 10 ) Communication (chapter 15 ) Control (chapter 16 ) Operations management (chapter 17 ) McGraw-Hill © 200 4 The ... Chapter 18 Managing Information Systems McGraw-Hill © 200 4 The McGraw-Hill Companies, Inc All rights reserved Learning Objectives After reading this chapter, you should be ... McGraw-Hill © 200 4 The McGraw-Hill Companies, Inc All rights reserved Information Related to MIS Management information systems provide access to important information used in many other chapters:...

Ngày tải lên: 09/12/2013, 15:15

... HREF="javascript:go('the Nile River')" COORDS= "1, 155,6 ,16 2 ,0 ,17 5,3,2 01 , 61 ,232 , 10 9,227 ,16 7 ,238 ,274 ,239 ,292,2 20, 307 ,2 20, 319 ,2 30 , 319 , 217 ,298, 213 ,282, 217 ,267 ,233 ,19 8,228 ,15 4,227 , 10 7,2 21 , 71, 225, 21, 199 ,19 ,16 5 ,0 ,14 9" ... Listing 18 - 1) to your tag Listing 18 - 1: Scripting image.complete function loadIt(theImage,form) { form.result.value = "" document.images [0] .src ... ALIGN=RIGHT>Image: Select...

Ngày tải lên: 10/12/2013, 15:15

... this might be your only choice isp.mm,v v4 . 10 ( 200 3 /04 /02 03 :09 :55) April 200 3, 17 :00 :47 The Complete FreeBSD ( /tools/tmac.Mn), page 317 317 Chapter 18 : Connecting to the Internet Establishing ... would change your telephone number isp.mm,v v4 . 10 ( 200 3 /04 /02 03 :09 :55) April 200 3, 17 :00 :47 The Complete FreeBSD ( /tools/tmac.Mn), page 319 319 Chapter 18 : Connecting to the Internet Choosing an ... the number of hops, the better isp.mm,v v4 . 10 ( 200 3 /04 /02 03 :09 :55) April 200 3, 17 :00 :47 The Complete FreeBSD ( /tools/tmac.Mn), page 3 21 3 21 Chapter 18 : Connecting to the Internet How many dialup...

Ngày tải lên: 11/12/2013, 00:15

... in 19 33 as a response to bank runs  About 5 , 10 0 banks failed during the Great Depression  Deposit insurance has increased from $2, 500 in 19 33 to $ 10 0, 000 today  Insured deposits make up 80 ... ranging from 23 cents to 31 cents per $ 10 0 of deposit In 200 3, three BIF-insured banks failed with total assets of $1. 1 billion As of 200 4, the BIF balance was about $34 billion In 19 91, the Federal ... pricing of Fed services Deregulation Act of 19 80 (cont’d)   DIDMCA also called for an increase in the maximum deposit insurance level from $ 40, 000 to $ 10 0, 000 per depositor Impact of DIDMCA  There...

Ngày tải lên: 12/12/2013, 23:15

... From Eq (18 . 19 ), m 3kT 3 (1. 3 81  10 23 J K)( 300 K)   1. 24  10 14 kg (0. 0 01 m s) v s2 b) mN A M  (1. 24  10 14 kg)(6. 02 3  10 23 molecules mol) (18 . 0  10 3 kg mol)  4 .16  10 11 molecules ... of 11 .0 L 18 . 54: m  nM   MpV RT (28 .0  10 3 kg mol)(2 .02 6  10 8 Pa)( 300 0  10 6 m ) (8. 314 5 J mol  K)(295 .15 K)  6.94  10 16 kg pVM RT (1. 05  10 Pa )( (1. 00 m)π (0. 0 60 m) )(44 . 10  10 3 ... 2(6. 21  10  21 J)     1. 24  10 19 N 2L v s L (0 . 10 0 m) L pave  Fave L2  1. 24  10 17 Pa    P Pave  1. 01 3  10 5 Pa 1. 24  10 17 Pa  8 .15  10 21 molecules pV NA RT   1. 00 atm 1. 00 ...

Ngày tải lên: 21/12/2013, 03:16

... lag Thus, x x SEPARATION BY NONSTATIONARITY OF VARIANCES 347 1 −2 −3 −4 10 00 200 0 300 0 400 0 500 0 600 0 700 0 800 0 900 0 10 00 0 Fig 18 . 1 A signal with nonstationary variance ICs of this kind could ... 349 14 12 10 0 10 0 200 300 400 500 600 700 800 900 10 00 Fig 18 . 2 The energy (i.e., squares) of the initial part of the signal in Fig 18 . 1 This is clearly time-correlated The algorithm in (18 . 27) ... J3 can be evaluated as @ J3 @W = X Q WC z (18 . 18 ) 2S with Q = diag(WCz WT ) X Q WC (18 . 19 ) Thus we obtain the gradient descent algorithm W/ z (18 . 20) 2S W Here, should be orthogonalized after...

Ngày tải lên: 20/01/2014, 11:20